This thread should be title ‘Rail Volume as percentage of thickness of the board’. But even that is entirely misleading.

Actually this is not a volume calculation, but an area comparison calculation.

Your formula is not very straightforward. But lets look at it and what is trying to be accomplished.

You basically want to compare a rectangular area at the center of the board to a somewhat comparable imaginary rectangular area at the rail.

They are comparable because you assume that both rectangles will share a width of **30 centimeters**, but differ in height.

thickness of board at center : 55 centimeters

so 55 x **30** = 1650 sq. centimeters

comparable imaginary rectangular area at rail:

36 x **30** = 1080 sq. centimeters

1080 / 1650 = .6545

take .6545 x 100= 65.45% for a percentage and you get the area of the imaginary rectangular area at the rail is 65% of the area of the rectangular area at the center.

Actually that imaginary rectangle out at the rail is really not there, it more approxiametly exists as half of that imaginary rectangle out at the rail(sliced at the hypotenuse), giving you a percentage number at closer to 32%

In addition, although the rectangle at the center of the board is a full rectangle, your picture dimensions for the imaginary rectangle out at the rail, dont cover the full real estate of the rail. Its quite arbitrarily reduced.

This doesnt’ pass muster, past the analysis of any mathematician. Its logic is full of holes.

I dont either particularly see the usefulness of this measurement, but if you can use it, thats all that counts.

In addition, I

dont see the avg. customer being able to give accurate measurements for

this. Unless they are equipped with a couple of specific calipers.

A ruler or yardstick in the avg. customers hand is not going to cut it.